Q. 745.0( 1 Vote )

Find the sum to n terms of the following series whose nth term is given by (2n – 1)2.



Answer :


Tn = (2n – 1)2

Tn = 4n2 – 4n + l

Sn = 4∑ n2 - 4∑ n + n
   
    =

    =

    =


    =

    =
    =

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