# Find the sum of the following series upto n terms 52 + 62 + 72 + ……+ 202

Tn of given series

= (nth term of 5, 6, 7,…..)2

= [5 + (n + 1).1]2

= (n + 4)2 = n2 + 8n + 16

Sn = ∑ n2 + 8∑ n + 16 × n

=

=

=

=

Put n = 16, then

S =

=

=

= 8 × 355 = 2840.

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