Answer :

We know that rms speed of gas is given by



Where R=gas constant 8.31J/molK


T=temperature of gas


M=molar mass of gas


Given


Temperature T=300K


Molar mass of hydrogen=2g/mol


Therefore,



Now in second part of question speed is doubled i.e. 21932.6ms-1


Let temperature at this speed be T1


So, using the same formula of rms speed



Squaring both sides of above equation




Temperature of the gas when speed is doubled is 1200K which is 4 times the pervious temperature.


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