Find the rms spee

We know that rms speed of gas is given by

Where R=gas constant 8.31J/molK

T=temperature of gas

M=molar mass of gas

Given

Temperature T=300K

Molar mass of hydrogen=2g/mol

Therefore,

Now in second part of question speed is doubled i.e. 21932.6ms^-1

Let temperature at this speed be T₁

So, using the same formula of rms speed

Squaring both sides of above equation

Temperature of the gas when speed is doubled is 1200K which is 4 times the pervious temperature.