Answer :
(i) 1 – i
x= rcosθ=1;y = rsinθ=−1
x + iy = 1 – i
x = 1, y = -1
r =

and tan θ = y/x = -1, θ =

Thus, the polar coordinates of 1 – i are (





(ii) –1 + i
x= rcosθ=−1;y = rsinθ=1
x + iy = -1 + i
x = -1, y = 1
r =
and tan θ = y/x = -1, θ = .
Thus, the polar coordinates of –1+ i are (,
) and its polar form is
(cos
+ i sin
).
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