Answer :

(i) 1 – i

x= rcosθ=1;y = rsinθ=−1

x + iy = 1 – i

x = 1, y = -1

r =

and tan θ = y/x = -1, θ = .

Thus, the polar coordinates of 1 – i are (, ) and its polar form is (cos + i sin).

(ii) –1 + i

x= rcosθ=−1;y = rsinθ=1

x + iy = -1 + i

x = -1, y = 1

r =

and tan θ = y/x = -1, θ = .

Thus, the polar coordinates of –1+ i are (, ) and its polar form is (cos + i sin).

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