Q. 14

Find the maximum kinetic energy of the photoelectrons ejected when light of wavelength 350 nm is incident on a cesium surface. Work function of cesium = 1.9 eV.

Answer :

Given, wavelength λ =350nm =350 ×m

Work function of cesium Ф =1.9eV


From Einstein photoelectric equation,


hf=Kmax +Ф


where Kmax is maximum kinetic energy,


h is Planck’s constant


f is frequency (f=c/λ where c is speed of light and


λ is the wavelength of light).







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