Q. 415.0( 1 Vote )
Find the magnetic field B due to a semicircular wire of radius 10.0 cm carrying a current of 5.0 A at its center of curvature.
Answer :
Given:
Radius of semicircular wire(r) = 10 cm = 0.1 m
Current carried by it(i) = 5 A
Formula used:
Magnetic field at the center of a semicircular loop =
Where
i = current carried by loop,
r = radius of loop,
𝛍0 = magnetic permeability of vacuum = 4π x 10-7 kg m s-2 A-2
Hence, required magnetic field(B) =
Tesla(T) ,
where 𝛍0 = 4π x 10-7 kg m s-2 A-2
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