Q. 75.0( 2 Votes )

Find the flux of the electric field through a spherical surface of radius R due to a charge of 10–7 C at the centre and another equal charge at a point 2R way from the centre.

Answer :


Magnitude of charges=10-7C

One at centre and another at a point 2R from centre.

We know that,

By Gauss’s law, flux of net electric field (E ) through a closed surface S equals the net charge enclosed (qin) by the surface divided by ϵ0



(Note that gauss’s law include only those charges which are enclosed by the closed surfaces and not the charges inside the surfaces)

Therefore flux through the sphere is given by



Therefore flux of electric field through a spherical surface of radius R is given by 1.1× 104Nm2/C

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Kirchoff's Law for VoltageFREE Class
Few Applications of Gauss's law54 mins
All About Faraday's law55 mins
Kirchoff's Voltage Law41 mins
Kirchoff's current & Voltage lawFREE Class
Questions based on Kirchoff's Law for Voltage67 mins
Ohm's Law - Full Concept in one Go59 mins
Interactive Quiz on Kirchoff's Law38 mins
NCERT Important Questions of Gauss's Law43 mins
Learn Raoult's Law56 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses