Q. 75.0( 2 Votes )

Find the flux of the electric field through a spherical surface of radius R due to a charge of 10–7 C at the centre and another equal charge at a point 2R way from the centre.



Answer :


Given:


Magnitude of charges=10-7C


One at centre and another at a point 2R from centre.


We know that,


By Gauss’s law, flux of net electric field (E ) through a closed surface S equals the net charge enclosed (qin) by the surface divided by ϵ0



Here,


C


(Note that gauss’s law include only those charges which are enclosed by the closed surfaces and not the charges inside the surfaces)


Therefore flux through the sphere is given by


Nm2/C


Nm2/C


Therefore flux of electric field through a spherical surface of radius R is given by 1.1× 104Nm2/C


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