To Find:The equation of the line with intercepts 4 and -6 on the x-axis and y-axis respectively.
Given : Let a and b be the intercepts on x-axis and y-axis respectively.
Then,x-intercept be a = 4
y-intercept be b = -6
we know that intercept form of a line is given by:
-3x + 2y = -12
3x – 2y -12 = 0
Hence 3x – 2y -12 = 0 is the required equation of the given line.
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