Answer :

It is given PQ is a wire of negligible resistance which travel smoothly over two conduction parallel wire X and Y separated by distance d and θ is the fixed angle made by PQ and B is the strength of the magnetic field perpendicular to the plane of the paper and outward

hence motion electric field = vB


the direction of this electric field is along CD perpendicular to


EMF of the induced in wire PQ


e = length of PQ * motional electric field QP




current in the wire


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