Answer :

In the given fig. Capacitors B and C are in parallel.


The formula for parallel combination of capacitor is


Ceq=C1+C2= CA +CB= 4 + 4 =8 μF


The formula for series combination of capacitors is



From the figure, the 8 μF is connected in series with Ceqv.


Thus, we get


Putting the values in the above equation, we get




Capacitors B and C are in parallel. CC


System of B,C and A has the same capacitor values. So they exhibit the same potential difference between them.


Hence Voltage across A is =6V


The voltage across B and C is = 6V


The charge can be calculated as



Where


Q is the charge of the capacitor


C is the Capacitance of the capacitor


V is the voltage across the circuit


Charge flows through A is QA = 8×6= 48μC


Charge flows through B is QB= 4×6 =24μC


Charge flows through C is QC= 4×6 = 24μC


Charge appearing on the capacitors A, B and C is 48μC, 24μC and 24μC respectively.


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