Q. 5

# Find the binding , here X = element
A = Mass Number[No. of protons + neutrons]

Z = Atomic Number [No. of protons]

Therefore, Number of neutrons(N)= A – Z

Now coming to the problem, means that A = 197 and Z = 79

N = A – Z = 197 – 79 = 118

Binding energy , mp = mass of proton

mn= mass of neutron

M = Atomic Mass

c2 = (Speed of light)2

= 931.5 MeV/u  Number of nucleons = No. of protons + neutrons = A = 197

Binding energy per nucleon Hence, the binding energy per nucleon = 7.741

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