Q. 14.1( 57 Votes )

# Find the

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Answer :

(a) X-ray produced by the electron therefore has maximum photon energy (E_{x}) equal to energy (E) of the electron.

E = eV …(1)

Where magnitude of charge of the electron ‘e’ = 1.6 × 10^{-19} C

Accelerating potential is V = 30 × 10^{3} V 3

Putting in equation (1) we get,

⇒ E = 1.6 × 10^{-19} C × 30 × 10^{3} J

Also, E_{x} = hν

Where, E_{x} = maximum energy of the X-ray

And h = plank’s constant = 6.63 × 10^{-34} J. sec

ν = max. frequency of X-ray

⇒ v_{max} = E_{max}/h

⇒

⇒ v_{max}= 7.24 × 10^{18} Hz

__Max. frequency of X-ray is 7.24 × 10 ^{18} Hz__

(b) Minimum wave length (λ) of X-ray is given by the following relation.

E_{x} = hν = hc/λ

∴ λ = hc / E_{x}

c = speed of light = 3 × 10^{8} m/s

⇒

⇒ λ = 0.041nm

__Minimum wave length of X-ray is equal to 0.041nm__

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