Answer :

The index of, is 7, which is an odd natural number.

So, Middle terms are and

= T_{4} = T_{3+1} = ^{7}C_{3}(3)^{7 – 3 }

= ^{7}C_{3}(3)^{4}(x^{3})^{3}(-1)(6^{-1})^{3}

= ^{7}C_{3}(81)(x)^{9} (6)^{-3}(-1)^{3}

= =

= T_{5} = T_{4} + 1 = ^{7}C_{4}(3)^{7 – 4 }

= ^{7}C_{4}(3)^{3 }(-1)^{4}(x^{3})(6)^{-4}

= ^{7}C_{4}(27)^{ }(x)^{12}(6)^{-4}

= (35)(27)(6)^{-4}(x)^{12}

= =

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