Answer :

(i) since resistances are connected in parallel

Therefore, effective resistance 1/R’ = 1/8+1/8 = 1/4

R’ = 4Ω

(ii) Current can be calculated with the help of Ohm’s law:

I = V/R = 8/4 = 2 A

(iii)Potential difference is given by, V= IR

V= 4 × 2 =8 Watt

(iv)Reading in ammeter A1, I = V/R = 8/4 = 2 A

Reading in ammeter A2 = 8/4

= 2 A

Difference in ammeter readings = 2- 2= 0

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