Answer :
(i) since resistances are connected in parallel
Therefore, effective resistance 1/R’ = 1/8+1/8 = 1/4
R’ = 4Ω
(ii) Current can be calculated with the help of Ohm’s law:
I = V/R = 8/4 = 2 A
(iii)Potential difference is given by, V= IR
V= 4 × 2 =8 Watt
(iv)Reading in ammeter A1, I = V/R = 8/4 = 2 A
Reading in ammeter A2 = 8/4
= 2 A
Difference in ammeter readings = 2- 2= 0
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