Q. 275.0( 1 Vote )
Find operation of the line passing through the point(2, 2) and cutting off intercepts on the axes whose sum is 9.
Answer :
Let the intercepts on the axes be a and b
Therefore, a + b = 9 ⇒ b = 9 – a
Now, equation of the line in intercept form is
= 1
or = 1
(2, 2) lies on it.
⇒ = 1
or = 1
or 18 = a(9 – a)
or 18 = 9a – a2
or a2 – 9a + 18 = 0
⇒(a – 6)(a – 3) = 0
Hence a = 3, 6
Case (i), When a = 3 ∴ b = 6
Equation of the line is
= 1
2x + y = 6 (Required line)
Case (ii), when a = 6, ∴ b = 3
Equation of the line is
= 1
x + 2y = 6 (Required equation)
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