# <span lang="EN-US

Given: a, 7, b, 23 and c are in AP.

To find: a, b and c

Formula Used:

d = a2 – a1 = a3 – a1 = __________ for n terms

Explanation:

For the above terms to be in AP.’

The difference of successive terms should be equal

i.e

a5 - a4 = a4 - a3 = a3 - a2 = a2 - a1 = d

where d let be common difference

7 - a = b - 7 = 23 - b = c - 23

Implies b - 7 = 23 - b

2b = 30

b = 15 ( eqn 1 )

Also

7 - a = b - 7

from eqn 1

7 - a = 15 - 7

a = - 1

and

c - 23 = 23 - b

c - 23 = 23 - 15

c - 23 = 8

c = 31

so a = - 1

b = 15

c = 31

and the sequence - 1, 7, 15, 23, 31 is an AP

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Arithmetic Progression and 'nth' Term of AP55 mins
Sum of n Terms of AP56 mins
Introduction of Geometric Progression60 mins
Imp Qs Practice For Boards (AP)59 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses