Q. 75.0( 2 Votes )

# <span lang="EN-US

Answer :

We know that work done by the gas is given as

ΔW=PΔV

From graph we can write

VA =VC = 10cc=10×10-6m3

VD=VB = 25cc= 25×10-6m3

PB=PC=30kPa= 30×103Pa

PA=PD=10kPa=10×103Pa

Work done in path ADB WADB=WAD + WDB

WADB = PA (VD-VA) + 0 ( WDB =0 because VD=VB)

=10×103×(25-10)×10-6

=0.15J

Work done in path AB WAB= Pavg(VB-VA) WAB=20×103× (25-10)×10-6

=0.30J

Work done in path ACB WACB= WAC+WBC

WACB = 0+PB(VB-VC) ( WAC=0 because VA=VC)

=30×103×(25-10)×10-6

=0.45J

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