# Figure shows a ci

Given-

Radius of the circular wire = a

Electric current passing through the loop = i

Magnetic field Perpendicular to the plane = B

(a) Magnetic force due to presence of current on a small differential length dl given by – where,

B= magnetic field

I = current

dl =differential length of the wire

and θ = the angle between B and dl

The direction of magnetic force,using Fleming’s left-hand rule is towards the centre for any differential length dl of the wire.

Also, dl and B are perpendicular to each other

(b) Suppose a part of loop subtends a small angle 2θ at the centre of a circular loop as shown in fig. Then, looking into the fig. we can say We know length l of an arc – where ,

r is radius of the circle and the angle subtended by the arc at the center

here, the arc is subtending an angle 2θ Since is small, sinθ will become negligible    Rate this question :

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