Answer :

Let the mass of the particle be m

Acceleration due to gravity, g = 9.8 m/s2


The height of the particle at point A, h = 1.0 m


Height of particle at the point where it terminates into straight horizontal section, h= 0.5 m


Applying energy conservation on the particle, total initial energy = total final energy


(Kinetic energy)initial + (Potential energy)initial = (Kinetic energy)final + (Potential energy)final


0 + mghat A = 1/2 mv2 + mghat point of termination


m×9.8×1 = 0.5×m×v2 + m×9.8×0.5


9.8 = 0.5v2 + 4.9


v2 = 9.8


v = 3.13 m/s


Let the time taken by particle to reach the termination point be t.


The particle starts sliding from rest, from the equation of motion


h = 1/2 gt2


0.5 = 0.5 × 9.8 × t2


t2 = 0.1020


t = 0.32 s


The horizontal distance that the particle will travel = speed v × time t


= 3.13 × 0.32


= 1.0016 ≈ 1m


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