Answer :

The force acting on any particle is mass(m) times acceleration(a).


Here, we need to find the acceleration from the above graphs.


From the x-t graph, we can see the relation that


x=t


And from the y-t curve,


y=t2


so,


ax = x’’ = 0 m s-2


ay = y’’ = 2 ms-2


So, the force is


Fx = 0


Fy = m x 2 = 0.5 x 2 = 1 N


Hence the force is 1N and is along y-axis.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Figure <span langPhysics - Exemplar

Figure <span langPhysics - Exemplar

A block of known HC Verma - Concepts of Physics Part 1

The energy of a sHC Verma - Concepts of Physics Part 1