Answer :

The force acting on any particle is mass(m) times acceleration(a).

Here, we need to find the acceleration from the above graphs.

From the x-t graph, we can see the relation that


And from the y-t curve,



ax = x’’ = 0 m s-2

ay = y’’ = 2 ms-2

So, the force is

Fx = 0

Fy = m x 2 = 0.5 x 2 = 1 N

Hence the force is 1N and is along y-axis.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

Figure <span langPhysics - Exemplar

Figure <span langPhysics - Exemplar

A block of known HC Verma - Concepts of Physics Part 1

The energy of a sHC Verma - Concepts of Physics Part 1