Answer :

The given figure represents simple harmonic motion (SHM).

Acceleration of a particle in simple harmonic motion is given by,

a = -ω^{2}x ………….. (1)

Where,

a = acceleration/deceleration

ω = angular frequency

x = path distance

And v = r ω

Where,

v = velocity

r = radial distance

From above graph,

At t = 0.3 s (lies between t=0 and t=1),

Position, x is Negative,

Velocity, v is Negative (negative slope), and

Acceleration, a is Negative (from equation 1)

At t = 1.2 s (lies between t=1 and t=2),

Position, x is Positive,

Velocity, v is Positive (negative slope), and

Acceleration, a is Negative (from equation 1)

At t = -1.2 s (lies between t=1 and t=2),

Position, x is Negative,

Velocity, v is Positive (negative slope), and

Acceleration, a is Positive (from equation 1)

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