Q. 79

Figure (10-E15) shows a small spherical ball of mass m rolling down the loop track. The ball is released on the linear portion at a vertical height H from the lowest point. The circular part shown has a radius R.

(a) Find the kinetic energy of the ball when it is at a point A where the radius makes an angle θ with the horizontal.

(b) Find the radial and the tangential accelerations of the center when the ball is at A.

(c) Find the normal force and the frictional force acting on the ball if H = 60 cm, R = 10 cm, θ = 0 and m = 70 g.

Answer :


Mass of the ball = m, radius of the circular path= R

Kinetic energy=

According to the question

c) at θ= 0 degree, the normal force is given as

Frictional force f is

f= mg - ma

= 0.07(10) – 0.70 (5/7) (10) = 0.2N

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
A Lecture on Head-on Collision49 mins
Pseudo Force52 mins
Inelastic collisions in 1 D44 mins
Understand Newton's 2nd law Exhaustively34 mins
Basics strengthener - Newton Laws of motion61 mins
Getting the basics of Gravitation51 mins
Motion in 1 D38 mins
Questions Based on Equilibrium of a particle37 mins
NLM HCV Objective | Interactive Quiz63 mins
Newton Laws of Motion (Lecture 7)FREE Class
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses