Answer :

Consider a parallel plate capacitor connected across a d.c. voltage supply as shown in the figure. When the circuit is closed, the electric current will flow through it. As the charges reaches to the plate, the insulating gap does not allow the charges to move further; hence, positive charges get deposited on one side of the plate and negative charges get deposited on the other side of the plate. When the voltage starts to develop, the electric charge begins to resist the deposition of further charge. Thus, the current flowing through the circuit gradually becomes less and then zero till the voltage of the capacitor is exactly equal but opposite to the voltage of the battery. This is how the capacitor gets charged when it is connected across a d.c. battery.



(a) The electric field between the plates is



The distance between plates is doubled, d' = 2d



Therefore, when the distance between the plates is double, the electric field will reduce


to one half.


(b) As the capacitance of the capacitor,



Energy stored in the capacitor is



Therefore, when the distance between the plates is doubled, the capacitance reduces to half. Therefore, energy stored in the capacitor becomes double.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

A capacitor is maPhysics - Exemplar

A parallel plate Physics - Exemplar

The battery remaiPhysics - Exemplar

A parallel-plate HC Verma - Concepts of Physics Part 2

How many time conHC Verma - Concepts of Physics Part 2

The plates of a cHC Verma - Concepts of Physics Part 2

A capacitor of caHC Verma - Concepts of Physics Part 2