In beta decay, a neutron decays into a proton, an electron and an antineutrino.n(neutrino) → e-(electron) + e+(proton) + 𝜈+(antineutrino)Example:6C8(Carbon) → 7N7(Nitrogen) + e-(electron) + 𝜈+(antineutrino)The radioactive decay law is given by N = N0e-λt, where N = final number of particles, N0 = initial number of particles, λ = decay constant, t = time.Now, , where t1/2 = half life.In this problem, t1/2 = 12.5 yrTherefore, Hence, after a time t = 25 years,Fraction remaining undecayed = (Ans)

Q. 24

Explain a beta de

Class 12th Physics - Exemplar 17. Sample Question Paper-2

Answer :

In beta decay, a neutron decays into a proton, an electron and an antineutrino.

n(neutrino) → e^-(electron) + e⁺(proton) + 𝜈⁺(antineutrino)

Example:

₆C⁸(Carbon) → ₇N⁷(Nitrogen) + e^-(electron) + 𝜈⁺(antineutrino)

The radioactive decay law is given by N = N₀e^-λt, where N = final number of particles, N₀ = initial number of particles, λ = decay constant, t = time.

Now, , where t_1/2 = half life.