Q. 355.0( 1 Vote )
Match the questions given under Column I with their appropriate answers given under the Column II.
Answer :
(a) Given: 
Here, 
, 
and 
Hence, the given numbers is in G.P with common ration 1/4
∴ (a) ↔ (iii)
(b) Given: 2, 3, 5, 7
Here, a2 – a1 = 3 – 2 = 1
a3 – a2 = 5 – 3 = 2
a4 – a3 = 7 – 5 = 2
∴ a2 – a1≠ a3 – a2
Hence, it is not in AP
Now, we will check the ratio
, 
So, 
So, it is not a G.P
Hence, it is a sequence
∴ (b) ↔ (ii)
(c) 13, 8, 3, -2, -7
Here, a2 – a1 = 8 – 13 = -5
a3 – a2 = 3 – 8 = -5
a4 – a3 = -2 – 3 = -5
∴ a2 – a1= a3 – a2
Hence, it is an AP
∴ (c) ↔ (i)
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