Q. 355.0( 1 Vote )

# Match the questions given under Column I with their appropriate answers given under the Column II.

Answer :

(a) Given:

Here, , and

Hence, the given numbers is in G.P with common ration 1/4

∴ (a) ↔ (iii)

(b) Given: 2, 3, 5, 7

Here, a_{2} – a_{1} = 3 – 2 = 1

a_{3} – a_{2} = 5 – 3 = 2

a_{4} – a_{3} = 7 – 5 = 2

∴ a_{2} – a_{1}≠ a_{3} – a_{2}

Hence, it is not in AP

Now, we will check the ratio

,

So,

So, it is not a G.P

Hence, it is a sequence

∴ (b) ↔ (ii)

(c) 13, 8, 3, -2, -7

Here, a_{2} – a_{1} = 8 – 13 = -5

a_{3} – a_{2} = 3 – 8 = -5

a_{4} – a_{3} = -2 – 3 = -5

∴ a_{2} – a_{1}= a_{3} – a_{2}

Hence, it is an AP

∴ (c) ↔ (i)

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