# If the sum of p t

The sum of n terms of an AP is given by Where a is the first term and d is the common difference

Given that Sp = q and Sq = p      Subtract (i) from (ii) that is (ii) – (i)  Using a2 – b2 = (a + b)(a – b)   We have to show that Sp+q = -(p + q)    Using (m) and (n)

Sp+q = Sp + Sq + pqd

= q + p + pqd

Substitute d from (iii) = (p + q) – 2(p + q)

= -(p + q)

Now we have to find sum of p – q terms that is Sp-q    Using (m) and (n)   Substitute d from (iii)      Hence sum of p – q terms is Rate this question :

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