# The following tab

(a) To convert the given frequency distribution into continuous form, adjust the end - limits of each class.

(b) To find median class,

Assume Σfi = N = Sum of frequencies,

fi = frequency

and Cf = cumulative frequency

So, N = 2300

N/2 = 2300/2 = 1150

The cumulative frequency just greater than (N/2 = ) 1150 is 1825, so the corresponding median class is 50.5 - 60.5.

median class = 50.5 - 60.5

The class mark of 50.5 - 60.5 is

(c) For modal class,

Here, the maximum class frequency is 529.

The class corresponding to this frequency is the modal class. modal class = 40.5 - 50.5

The cumulative frequency corresponding to the modal class is 1330

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Resources and Development Revision28 mins
Cube and Cuboid41 mins
History - Concept and Questions57 mins
Sphere and Hemisphere16 mins
Heights and Distances-I45 mins
Corrosion: Types, Pros and Cons41 mins
Right Circular Cylinder45 mins
Right Circular Cone And Frustum43 mins
Revision on Substitution and Elimination Method44 mins
Magnetic Field of Circular Conductor41 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses