Answer :

(a) To convert the given frequency distribution into continuous form, adjust the end - limits of each class.



(b) To find median class,


Assume Σfi = N = Sum of frequencies,


fi = frequency


and Cf = cumulative frequency



So, N = 2300


N/2 = 2300/2 = 1150


The cumulative frequency just greater than (N/2 = ) 1150 is 1825, so the corresponding median class is 50.5 - 60.5.


median class = 50.5 - 60.5


The class mark of 50.5 - 60.5 is


(c) For modal class,


Here, the maximum class frequency is 529.


The class corresponding to this frequency is the modal class. modal class = 40.5 - 50.5


The cumulative frequency corresponding to the modal class is 1330


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