Q. 203.7( 3 Votes )
The following tab
(a) To convert the given frequency distribution into continuous form, adjust the end - limits of each class.
(b) To find median class,
Assume Σfi = N = Sum of frequencies,
fi = frequency
and Cf = cumulative frequency
So, N = 2300
⇒ N/2 = 2300/2 = 1150
The cumulative frequency just greater than (N/2 = ) 1150 is 1825, so the corresponding median class is 50.5 - 60.5.
∴ median class = 50.5 - 60.5
The class mark of 50.5 - 60.5 is
(c) For modal class,
Here, the maximum class frequency is 529.
The class corresponding to this frequency is the modal class. ⇒ modal class = 40.5 - 50.5
The cumulative frequency corresponding to the modal class is 1330
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