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# If 35Cn+7 = 35C4n–2 then find the value of n.

Given: 35Cn+7 = 35C4n–2 Need to find: Value of n We know, one of the property of combination is: If nCr = nCt, then, (i) r = t OR (ii) r + t = n Applying property (i) we get, n + 7 = 4n – 2 3n = 9 n = 3 Applying property (ii) we get, n + 7 + 4n – 2 = 35 5n = 30 n = 6 Therefore, the value of n is either 3 or 6.

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