# The agewise parti

To find frequencies, we have Sum of frequencies that is, 181.

Using Sum of frequencies = 181,

x + 15 + 18 + 30 + 50 + 48 + x = 181

2x + 161 = 181

2x = 181 – 161 = 20

x = 10

Thus we have,

Here, the maximum class frequency is 50.

The class corresponding to this frequency is the modal class. modal class = 13 - 15

lower limit of the modal class (l) = 13

Modal class size (h) = 2

Frequency of the modal class (f1) = 50

Frequency of class preceding the modal class (f0) = 30

Frequency of class succeeding the modal (f2) = 48

Mode is given by,

Mode = 13 + 1.82 = 14.82

Hence, the mode is 14.82.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Arithmetic Progression and 'nth' Term of AP55 mins
Chemical Properties of Metal and Non Metal61 mins
Extraction of Metal56 mins
Purification of Metals60 mins
Introduction of Metal and Non Metal59 mins
Properties of Metal and Non Metal59 mins
Trigo Marathon Part 245 mins
Application of Trigo Important Questions44 mins
Trigo Marathon Part 146 mins
Heights and Distances - I54 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses