Q. 94.0( 29 Votes )

# In the following

Answer :

Given: Median = 5000 & N = 60

Assume

Σfi = N = Sum of frequencies,

h = length of median class,

l = lower boundary of the median class,

f = frequency of median class

and Cf = cumulative frequency

Lets form a table, where x is the unknown frequency. Given,
Median = 5000 (as already mentioned in the question)

Sum of frequencies, N = x + y + 25 = 60 [Total No of players]

5000 lies between 4500 - 5500 Median class = 4500 - 5500

l = 4500, h = 1000, f = y, N/2 = 60/2=30
and Cf = 5 + x

Median is given by,   5000 – 4500 = (25000 – 1000x)/y

500y = 25000 – 1000x

2x + y = 50 …(i)

And given that N = 60

25 + x + y = 60

x + y = 35 …(ii)

Solving equations (i) & (ii), we get

(2x + y) – (x + y) = 50 – 35

x = 15

Substituting x = 15 in eq.(ii),

15 + y = 35

y = 20

Thus, the unknown frequencies are x = 15 and y = 20.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Arithmetic Progression and 'nth' Term of AP55 mins  Chemical Properties of Metal and Non Metal61 mins  Extraction of Metal56 mins  Purification of Metals60 mins  Properties of Metal and Non Metal59 mins  Introduction of Metal and Non Metal59 mins  Trigo Marathon Part 245 mins  Trigo Marathon Part 146 mins  Heights and Distances - II45 mins  Heights and Distances - I54 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 