In the following

Given: Median = 5000 & N = 60

Assume

Σf_i = N = Sum of frequencies,

h = length of median class,

l = lower boundary of the median class,

f = frequency of median class

and C_f = cumulative frequency

Lets form a table, where x is the unknown frequency.

Given,
Median = 5000 (as already mentioned in the question)

Sum of frequencies, N = x + y + 25 = 60 [Total No of players]

5000 lies between 4500 - 5500 ⇒ Median class = 4500 - 5500

∴ l = 4500, h = 1000, f = y, N/2 = 60/2=30
and C_f = 5 + x

Median is given by,

⇒

⇒

⇒ 5000 – 4500 = (25000 – 1000x)/y

⇒ 500y = 25000 – 1000x

⇒ 2x + y = 50 …(i)

And given that N = 60

⇒ 25 + x + y = 60

⇒ x + y = 35 …(ii)

Solving equations (i) & (ii), we get

(2x + y) – (x + y) = 50 – 35

⇒ x = 15

Substituting x = 15 in eq.(ii),

15 + y = 35

⇒ y = 20

Thus, the unknown frequencies are x = 15 and y = 20.