Answer :

To find median, Assume

Σfi = N = Sum of frequencies,


h = length of median class,


l = lower boundary of the median class,


f = frequency of median class


and Cf = cumulative frequency


Lets form a table.



So, N = 100


N/2 = 100/2 = 50


The cumulative frequency just greater than (N/2 = ) 50 is 56, so the corresponding median class is 150 - 155 and accordingly we get Cf = 34(cumulative frequency before the median class).


Now, since median class is 150 - 155.


l = 150, h = 5, f = 22, N/2 = 50 and Cf = 34


Median is given by,




= 150 + 3.636


= 153.64


Thus, median is 153.64 cm.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Arithmetic Progression and 'nth' Term of APArithmetic Progression and 'nth' Term of APArithmetic Progression and 'nth' Term of AP55 mins
Chemical Properties of Metal and Non MetalChemical Properties of Metal and Non MetalChemical Properties of Metal and Non Metal61 mins
Extraction of MetalExtraction of MetalExtraction of Metal56 mins
Purification of MetalsPurification of MetalsPurification of Metals60 mins
Introduction of Metal and Non MetalIntroduction of Metal and Non MetalIntroduction of Metal and Non Metal59 mins
Properties of Metal and Non MetalProperties of Metal and Non MetalProperties of Metal and Non Metal59 mins
Trigo Marathon Part 2Trigo Marathon Part 2Trigo Marathon Part 245 mins
Application of Trigo Important QuestionsApplication of Trigo Important QuestionsApplication of Trigo Important Questions44 mins
Trigo Marathon Part 1Trigo Marathon Part 1Trigo Marathon Part 146 mins
Heights and Distances - IHeights and Distances - IHeights and Distances - I54 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses