ABCD is parallelogram.

We know that the sum of the adjacent angles in parallelogram is 180°

A + B = 180°

+ = = 90°

In ∆ APB, we have:
PAB = A /2
PBA = B /2
APB = 180 − (PAB + PBA) …Angle sum property of triangle
APB = 180 – ( + )
APB = 180 − 90 = 90°
Hence, proved.

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