Answer :

Since the committee of 11 is to be formed from 6 teachers and 8 students.


(i) Forming a committee with exactly 4 teachers


Choosing 4 teachers out of 6 in 6C4 ways.


Remaining 7 from 8 students in 8C7 ways.


Thus, total ways in (i) are 6C4 8C7 ways.


(ii) The number of ways in this case is


1. 4 teachers and 7 students


2. 5 teachers and 6 students


3. 6 teachers and 5 students


= 6C48C7+6C58C66C68C5


Applying nCr =


= 344 ways


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