Q. 135.0( 1 Vote )

In an examination

Answer :

There are total 13 questions out of which 10 is to be answered .The student can answer in the following ways:


3 questions from part A and 4 from part B


4 questions from part A and 3 from part B


5 questions from part A and 2 from part B


2 questions from part A and 5 from part B


total ways in the 1st case are 6C36C4


total ways in the 2nd case are 6C46C3


total ways in the 3rd case are 6C56C2


total ways in the 4th case are 6C26C5


=6C46C3+6C36C46C56C2+ 6C26C5


Applying nCr =


= 780 ways.


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