Q. 104.5( 13 Votes )
Let ABCD be rhombus.
Here, AC and BD are the diagonals of ABCD, where AC = 24 cm and BD = 18 cm.
Let the diagonals intersect each other at O.
We know that the diagonals of a rhombus are perpendicular bisectors of each other.
∴ ∆AOB is a right angle triangle in which OA = = 12 cm and OB = = 9 cm.
Now, AB2= OA2 + OB2 …Pythagoras theorem
∴ AB2= (12)2 + (9)2
∴ AB2= 144 + 81 = 225
∴ AB = 15 cm
Hence, the side of the rhombus is 15 cm
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