Q. 333.7( 8 Votes )

# Aman saved Rs. 16500 in ten years. In each year after the first he saved Rs.100 more than he did in the preceding year. How much did he save in the first year?

Answer :

Given,

Man saved in 10 years, S_{10}= 16500

In each year after first he saved, d = 100

We know, sum of n terms, S_{n}= [2a + (n – 1) d]

For 10 years

S_{10}= [2a + (10 – 1) 100]

16500 = 5 [2a + 9 * 100]

= 2a + 900

3300 = 2a + 900

2a = 3300 – 900

2a = 2400

a = 1200

Hence, Rs. 1200 saved by him in first year

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PREVIOUSLet there be an A.P. with first term ‘a’, common difference, d. Ifdenotes its nth term andthe sum of first n terms, find.(i)(ii)(iii)(iv)(v)(vi)NEXTAman saved Rs.32 during the first year, Rs.36 in the second year and in this way he increases his savings by Rs.4 every year. Find in what time his saving will be Rs.200.

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