Answer :
Given,
Man saved in 10 years, S10= 16500
In each year after first he saved, d = 100
We know, sum of n terms, Sn= [2a + (n – 1) d]
For 10 years
S10= [2a + (10 – 1) 100]
16500 = 5 [2a + 9 * 100]
= 2a + 900
3300 = 2a + 900
2a = 3300 – 900
2a = 2400
a = 1200
Hence, Rs. 1200 saved by him in first year
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