Answer :

Given,

Man saved in 10 years, S10= 16500


In each year after first he saved, d = 100


We know, sum of n terms, Sn= [2a + (n – 1) d]


For 10 years


S10= [2a + (10 – 1) 100]


16500 = 5 [2a + 9 * 100]


= 2a + 900


3300 = 2a + 900


2a = 3300 – 900


2a = 2400


a = 1200


Hence, Rs. 1200 saved by him in first year


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