Q. 34.3( 15 Votes )

Find the four numbers in A.P. whose sum is 50 and in which the greatest number is 4 times the least.

Answer :

Let the four numbers be (a – 3d), (a – d), (a + d) and (a + 3d)

a – 3d + a – d + a + d + a + 3d = 50


4a = 50


a =


According to question,


(a + 3d) = 4(a – 3d)


a + 3d = 4a – 12d


3a = 15d


5d =


d =


Therefore,


a – 3d = - = 5


a – d = - = 10


a + d = + = 15


a + 3d = + = 20


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