Q. 75.0( 1 Vote )

# If 0 < θ <

cos(90–θ ) = sinθ

tan(90–θ ) = cotθ

sin(90–θ ) = cosθ

cot(90–θ ) = tanθ

cosec(90–θ ) = secθ

sec(90–θ) = cosecθ

sinθ = cos30

θ = 60

Now, 2tan2θ – 1

= 2tan260 – 1

= 2(√3)2 – 1

= 5

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