Q. 75.0( 1 Vote )

# If 0 < θ < 90, θ, sinθ = cos30, then obtain the value of 2tan2θ — 1.

cos(90–θ ) = sinθ

tan(90–θ ) = cotθ

sin(90–θ ) = cosθ

cot(90–θ ) = tanθ

cosec(90–θ ) = secθ

sec(90–θ) = cosecθ

sinθ = cos30

θ = 60

Now, 2tan2θ – 1

= 2tan260 – 1

= 2(√3)2 – 1

= 5

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Champ Quiz | NTSE Trigonometry50 mins
Testing the T- Ratios of Specified Angles57 mins
Foundation | Cracking Previous Year IMO Questions59 mins
Trigonometry Basics36 mins
Smart Revision | Lets Revise Trigonometry45 mins
Champ Quiz | Trigonometry Important Questions33 mins
Solving NCERT Questions on Trigonometric Identities56 mins
Smart Revision | Revise Trigo Like an Expert51 mins
NCERT I Trigonometric Ratios50 mins
Champ Quiz | Trigger on Trigonometry47 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses