# Find the number of all three digit natural numbers which are divisible by 9.

Let the three digit numbers divisible by 9 are

108, 117, 126,… ,999

a=108, d=9, last term, l= 999

Number of terms, n = +1

= + 1

= +1

=100

Hence, the number of all three digit natural numbers which are divisible by 9 are 100

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