# Find the number of all three digit natural numbers which are divisible by 9.

Let the three digit numbers divisible by 9 are

108, 117, 126,… ,999

a=108, d=9, last term, l= 999

Number of terms, n = +1

= + 1

= +1

=100

Hence, the number of all three digit natural numbers which are divisible by 9 are 100

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Champ Quiz | Arithmetic Progression34 mins
Champ Quiz | Arithmetic Progression30 mins
Quiz | Arithmetic Progression44 mins
NCERT | Fundamental Theorem Of Arithmetic45 mins
Lets Check Your Knowledge in A.P.49 mins
Arithmetic progression: Previous Year NTSE Questions34 mins
NCERT | Questions on General Term of an A.P47 mins
Sum of n Terms of an AP36 mins
Arithmetic Progression Tricks and QUIZ37 mins
Quiz | Group of Questions on General Term of an A.P49 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses