Answer :
Given: there were 30 bacteria present originally and culture doubles every hour.
∴ a0 = 30
∴ After an hour culture is a0 × 2 = 30 × 2 = 60
Since the count doubles every hour it forms a G.P. with r = 2
Let the G.P be a0,a1r,a2r2........
⇒ The culture at the end of 2nd hour = ar2 = 30 × 22 = 120
⇒ The culture at the end of 4th hour = ar4 = 30 × 24 = 480
⇒ The culture at the end of nth hour = arn = 30 × 2n
∴ Culture at end pf 2nd , 4th , nth hours are 120, 480, 30 × 2n respectively.
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