Answer :

Given, a = a

Last term, l = l


We have to prove that the sum of the mth term from the beginning and mth term from the end is (a + 1)


Now, mth term from the beginning,


am(b) = a + (m – 1) l


= a + ml – l (i)


Again mth term from the end


am(e) = l – (m – 1)l


= l – ml + l = 2l – ml (ii)


By adding (i) and (ii), we get


a + ml – l + 2l – ml = a + l


Hence, proved


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