Q. 144.4( 208 Votes )

# In Fig.9.28, AP |

Answer :

Since ΔABQ and ΔPBQ lie on the same base BQ and are between the same parallels AP and BQ

Area (ΔABQ) = Area (ΔPBQ) (i)

Again, ΔBCQ and ΔBRQ lie on the same base BQ and are between the same parallels BQ and CR

Area (ΔBCQ) = Area (ΔBRQ) (ii)

On adding equations (i) and (ii), we obtain

Area (ΔABQ) + Area (ΔBCQ) = Area (ΔPBQ) + Area (ΔBRQ)

**Area (ΔAQC) = Area (ΔPBR)**

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