Answer :

Since ΔABQ and ΔPBQ lie on the same base BQ and are between the same parallels AP and BQ

Area (ΔABQ) = Area (ΔPBQ) (i)


Again, ΔBCQ and ΔBRQ lie on the same base BQ and are between the same parallels BQ and CR


Area (ΔBCQ) = Area (ΔBRQ) (ii)


On adding equations (i) and (ii), we obtain


Area (ΔABQ) + Area (ΔBCQ) = Area (ΔPBQ) + Area (ΔBRQ)


Area (ΔAQC) = Area (ΔPBR)

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