Answer :


i. Let Major segment A1 minor segment be A2


∠A = 90°







area of sector ACD = 78.5cm2


Pythagoras


AC2 = CD2 + AD2


AC2 = 102 + 102


AC2 = 200


AC = 10


Height of triangle =


Cos 45° =



AE =


Area of minor segment = Area of sector ACD – Area ΔACD


= 78.5 –10


= 78.5-50


= 28.5 cm2


ii. Major segment = Area of circle – minor segment


= π × r2 –minor segment


= π × 102 –28.5


= 314-28.5


= 285.5cm2


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