# A chord of a circ

i. Let Major segment A1 minor segment be A2

∠A = 90°

area of sector ACD = 78.5cm2

Pythagoras

AC2 = 102 + 102

AC2 = 200

AC = 10

Height of triangle =

Cos 45° =

AE =

Area of minor segment = Area of sector ACD – Area ΔACD

= 78.5 –10

= 78.5-50

= 28.5 cm2

ii. Major segment = Area of circle – minor segment

= π × r2 –minor segment

= π × 102 –28.5

= 314-28.5

= 285.5cm2

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