# Write the sequenc

(i) Put n = 1

A1= 3 + 4(1) = 7

Put n = 2

A2= 3 + 4(2) = 11

Put n = 3

A3= 3 + 4(3) = 15

Common difference, d1= a2 – a1 = 11 – 7 = 4

Common difference, d2= a3 – a2 = 15 – 11 = 4

Since, d1 = d2

Therefore, it’s an A.P. with sequence 7, 11, 15,…

(ii) Put n = 1

A1= 5 + 2(1) = 7

Put n = 2

A2= 5 + 2(2) = 9

Put n = 3

A3= 5 + 2(3) = 11

Common difference, d1= a2 – a1= 9 – 7 = 2

Common difference, d2= a3 – a2= 11 – 9 = 2

Since, d1 = d2

Therefore, it’s an A.P. with sequence 7, 9, 11,…

(iii) Put n = 1

A1= 6 – 1 = 5

Put n = 2

A2= 6 – 2 = 4

Put n = 3

A3= 6 – 3 = 3

Common difference, d1= a2 – a1= 4 – 5 = -1

Common difference, d2 = a3- a2= 3 – 4 = -1

Since, d1=d2

Therefore, it’s an A.P. with sequence 5, 4 , 3,…

(iv) Put n = 1

A1= 9 – 5(1) = 4

Put n = 2

A2= 9 – 5(2) = -1

Put n = 3

A3= 9 – 5(3) = -6

Common difference, d1= a2 – a1 = -1 – 4 = -5

Common difference,d2= a3 – a2 = -6 – (-1) = -5

Since, d1=d2

Therefore, it’s an A.P. with sequence 4, -1, -6,…

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