Q. 9

In a Δ ABC, AD bisects A and C >B. Prove that ADB >ADC.

Answer :


AB bisects A (DAB = DAC)

C > B

In ,

ADB + DAB + B = 180o (i)

In ,

ADC + DAC + C = 180o (ii)

From (i) and (ii), we get

ADB + DAB + B = ADC + DAC + C

ADB > ADC (Therefore, C > B)

Hence, proved

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Quiz | Angle Sum Property of Triangle40 mins
Quiz | Lines and Angles43 mins
Quiz | Lines and Angles40 mins
Lines and Angles45 mins
NCERT | Angle Sum Property44 mins
Matter and Its Classification34 mins
NCERT | Intersecting and Non Intersecting lines)41 mins
NCERT | Discussion on Lines And Angles45 mins
Know About Transversal and Parallel lines42 mins
Quiz on Lines and Angles26 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses