Answer :

AB = BC = 3.5 cm and DE = 2cm

⇒ DC = DE + EC = 2 + 3.5 = 5.5 cm

As we know that,

Height of trapezium here, BC = 3.5 cm

⇒ A_{T} = 15.75 sq.cm

Now, area of quarter circle = A_{Q}

⇒ A_{Q} = 9.625 sq.cm

Required area = A_{T} – A_{Q}

⇒ Req. area = 15.75 – 9.625 = 6.125 sq.cm

∴ Area of remaining piece of cardboard is 6.125 sq.cm

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