Q. 84.6( 49 Votes )

On the occasion o

Answer :

We have

For mean:

Mean is given by

Mean = 80

For median:

Total observation, N = 150

Since, N is even (that is, 150 is even),


Cumulative frequencies = 88 is just greater than 75 and 76.

And cumulative frequencies, 75 and 76 falls in cost of packet, ‘75.

Median = 75

For mode:

Mode is the value having highest frequency in the data.

From the table given above, 36 is the greatest frequency in the given frequencies.

Thus, the corresponding value in ‘cost of packet’, 50 is the mode.

Mode = 50

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