Q. 84.9( 9 Votes )

In Fig. 9.37, AM BC and AN is the bisector of A. If B =65° and C =33°, find MAN.


Answer :

Given,

AM perpendicular to BC


AN is bisector of A


Therefore, NAC = NAB


In


A + B + C = 180o


A + 65o + 33o = 180o


A = 180o – 98o


= 82o


NAC = NAB = 41o (Therefore, AN is bisector of A)


In


AMB + MAB + ABM = 180o


90o + MAB + 65o = 180o


MAB + 155o = 1800


MAB = 25o


Therefore,


MAB + MAN = BAN


25o + MAN = 41o


MAN = 41o – 25o


= 16o


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