# Find the sum to n terms of the A.P., whose kth term is 5k + 1.

Let the first term be a and common difference be d.

Given that kth term of the A.P. is 5k + 1.

kth term = ak = a + (k – 1)

a + (k – 1)d = 5k + 1  d k + (a - d) = 5k + 1

Comparing the coefficient of k, we obtain d = 5 and a – d = 1

a – 5 = 1

a = 6

Putting the value of a and d

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