Answer :

Step1:Draw circles of radius 4 and 6 cm

Step 3: Draw tangent to inner circle from C

AD is perpendicular to DC- tangent and radius

In Δ ADC

AC is radius

AC^{2} = AD^{2} + DC^{2}

6^{2} = 4^{2} + DC^{2}

36 = 16 + DC^{2}

DC^{2} = 20

DC = 2 cm

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